Author: lllyouo
Date: 20250424
tag: tarjan、强连通分量、拓扑排序
link: https://www.acwing.com/problem/content/370/问题描述
分析
略
参考代码
cpp
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10, M = 3e5 + 10;
int h[N], e[M], w[M], ne[M], idx;
int hc[N], ec[M], wc[M], nec[M], idxc;
int dfn[N], low[N], ins[N], c[N], st[N], top, num, cnt;
int n, m, in[N], d[N];
void add(int a, int b, int c) {
e[idx] = b;
w[idx] = c;
ne[idx] = h[a];
h[a] = idx++;
}
void add_c(int a, int b, int c) {
ec[idxc] = b;
wc[idxc] = c;
nec[idxc] = hc[a];
hc[a] = idxc++;
}
void tarjan(int x) {
dfn[x] = low[x] = ++num;
st[++top] = x;
ins[x] = true;
for (int i = h[x]; i != -1; i = ne[i]) {
int y = e[i];
if (!dfn[y]) {
tarjan(y);
low[x] = min(low[x], low[y]);
} else if (ins[y]) {
low[x] = min(low[x], dfn[y]);
}
}
if (dfn[x] == low[x]) {
cnt++;
int y;
do {
y = st[top--], ins[y] = false;
c[y] = cnt;
} while (x != y);
}
}
void topsort() {
queue<int> q;
for (int i = 1; i <= cnt; i++) {
if (in[i] == 0) q.push(i);
}
while (q.size()) {
int x = q.front();
q.pop();
for (int i = hc[x]; i != -1; i = nec[i]) {
int y = ec[i];
d[y] = max(d[y], d[x] + wc[i]);
if (--in[y] == 0) q.push(y);
}
}
}
int main() {
memset(h, -1, sizeof h);
memset(hc, -1, sizeof hc);
cin >> n >> m;
for (int i = 1; i <= m; i++) {
int o, x, y; cin >> o >> x >> y;
if (o == 1) add(x, y, 0), add(y, x, 0);
else if (o == 2) add(x, y, 1);
else if (o == 3) add(y, x, 0);
else if (o == 4) add(y, x, 1);
else add(x, y, 0);
}
for (int i = 1; i <= n; i++) add(0, i, 1);
for (int i = 0; i <= n; i++) {
if (!dfn[i]) tarjan(i);
}
for (int x = 0; x <= n; x++) {
for (int i = h[x]; i != -1; i = ne[i]) {
int y = e[i];
if (c[x] == c[y]) {
if (w[i] == 1) {
puts("-1");
return 0;
}
} else {
add_c(c[x], c[y], w[i]);
in[c[y]]++;
}
}
}
topsort();
long long ans = 0;
for (int i = 1; i <= n; i++) ans += d[c[i]];
cout << ans << endl;
return 0;
}